مرحبا ...
انا عضو جديد هنا .. و عندي مشكله و أتمنه المساعدة السريعة
i wrote a JApplet chat application
and this is the sourse code for the server
import javax.swing.*;
import java.awt.event.*;
import java.awt.*;
import java.io.*;
import java.net.*;
public class Server extends JApplet implements ActionListener
{
JButton btn;
JTextArea main;
JTextField msg;
String maintxt ="";
JLabel labl;
String message = "";
Socket socket = null;
ServerSocket srv = null;
public void init()
{
Container cont = getContentPane();
cont.setBackground(Color.gray);
cont.setLayout(new FlowLayout());
main= new JTextArea("",10,20);
labl = new JLabel("Server");
btn = new JButton("Send");
btn.addActionListener(this);
msg = new JTextField(25);
cont.add(labl);
cont.add(new JScrollPane(main));
cont.add(msg);
cont.add(btn);
Recive r = new Recive();
r.start();
}
public void actionPerformed(ActionEvent ev)
{
if (ev.getSource() == btn)
{
maintxt +=msg.getText()+"\n";
main.setText(maintxt);
try{
OutputStream out = socket.getOutputStream();
message = msg.getText();
out.write(message.getBytes());
msg.setText("");
msg.setText("");
}
catch(Exception ex)
{
System.out.println(ex);
}
}
}
class Recive extends Thread
{
public void run()
{
try {
int port = 5555;
srv = new ServerSocket(port);
socket = srv.accept();
while (true)
{
InputStream in = socket.getInputStream();
byte[]b = new byte[1024];
in.read(b);
String s = new String(b);
maintxt +=s.trim()+"\n";
main.setText(maintxt);
}
}
catch (Exception e)
{
System.out.println(e);
}
}
}
}
and this the client
import javax.swing.*;
import java.awt.event.*;
import java.awt.*;
import java.io.*;
import java.net.*;
import javax.swing.JTextField;
public class Client extends JApplet implements ActionListener
{
JButton btn;
JTextArea main;
JTextField msg;
JLabel labl;
String maintxt ="";
Socket socket = null;
OutputStream out = null;
public Client()
{
try
{
InetAddress addr = InetAddress.getByName("my ip");
int port = 5555;
socket = new Socket(addr, port);
}
catch(Exception ex)
{
System.out.println(ex);
}
}
public void init()
{
Container cont = getContentPane();
cont.setBackground(Color.gray);
cont.setLayout(new FlowLayout());
main= new JTextArea("",10,20);
//txt.setColumns(20);
//txt.setRows(10);
btn = new JButton("Send");
btn.addActionListener(this);
msg = new JTextField(25);
labl = new JLabel("Client");
cont.add(labl);
cont.add(new JScrollPane(main));
cont.add(msg);
cont.add(btn);
Recive r = new Recive();
r.start();
}
public void actionPerformed(ActionEvent ev)
{
if (ev.getSource() == btn)
{
maintxt +=msg.getText()+"\n";
main.setText(maintxt);
BufferedReader input = null;
String message = "";
try {
message = msg.getText();
out = socket.getOutputStream();
out.write(message.getBytes());
msg.setText("");
}
catch (Exception e)
{
System.out.println(e);
}
}
}
class Recive extends Thread
{
public void run()
{
try {
while (true)
{
InputStream in = socket.getInputStream();
System.out.println("in client while");
byte[]b = new byte[1024];
in.read(b);
String s = new String(b);
maintxt +=s.trim()+"\n";
main.setText(maintxt);
}
}
catch (Exception e)
{
System.out.println(e+"in thread");
}
}
}
}
and this is the client html page thats contain the applet(Client.html)
<html>
<head>
</head>
<body>
<applet code=Client.class width=400 height=400 codebase = "http://myip:8080/Chat1">
</applet>
</body>
</html>
so
this application works fine on my computer, that means the server and the client can chat toguther on my computer
but
when another computer on the LAN used the application by (Client.html)
the server gives me this
EXCeption
Why , and what is the solution
java.security.AccessControlException: access denied (java.net.SocketPermission
myip:1210 accept,resolve)
thanx alot
